Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 4.84.
The square root is the inverse of the square of the number. 4.84 is a perfect square. The square root of 4.84 is expressed in both radical and exponential form. In radical form, it is expressed as √4.84, whereas (4.84)^(1/2) in exponential form. √4.84 = 2.2, which is a rational number because it can be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, for non-perfect square numbers, methods like long-division and approximation are also used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now, let us look at how 4.84 is broken down into its prime factors:
Step 1: Convert 4.84 to a fraction, which is 484/100.
Step 2: Find the prime factors of 484, which are 2 x 2 x 11 x 11: \(2^2 \times 11^2\).
Step 3: The prime factorization of 100 is 2 x 2 x 5 x 5: \(2^2 \times 5^2\).
Step 4: Take the square root of both numerator and denominator separately: √484/√100 = 22/10 = 2.2.
The long division method is particularly used for non-perfect square numbers. However, since 4.84 is a perfect square, we can also use it to verify the result.
Step 1: To begin with, we need to place 4.84 under the division symbol.
Step 2: Find a number whose square is less than or equal to 4. The number is 2, whose square is 4.
Step 3: Subtract 4 from 4, the remainder is 0. Bring down the next pair, which is 84.
Step 4: Double the quotient to get the new divisor, which is 4. Now, find a digit to place after this 4 so that the product is less than or equal to 84. The digit is 2 making it 42. 42 x 2 = 84.
Step 5: Subtract 84 from 84, the remainder is 0. So, the square root of √4.84 is 2.2.
The approximation method is another way to find square roots; it is useful for quick estimates. However, since 4.84 is a perfect square, we can use it to confirm the result.
Step 1: Identify two perfect squares between which 4.84 lies.
4 (2^2) and 9 (3^2) are perfect squares, and 4.84 lies between them.
Step 2: Since 4.84 is closer to 4, estimate that the square root is slightly more than 2.
Step 3: Calculate (4.84 - 4) / (9 - 4) to find a more precise estimate, which will indicate how much more than 2 the square root should be.
Step 4: Refine the estimate to 2.2, which is the exact square root of 4.84.
Students may make mistakes while finding the square root, like forgetting about the negative square root or skipping steps in methods. Now let us look at a few of those mistakes that students tend to make in detail.
Can you help Max find the area of a square box if its side length is given as √4.84?
The area of the square is 4.84 square units.
The area of the square = side^2.
The side length is given as √4.84.
Area of the square = side^2 = √4.84 x √4.84 = 2.2 × 2.2 = 4.84.
Therefore, the area of the square box is 4.84 square units.
A square-shaped building measuring 4.84 square feet is built; if each of the sides is √4.84, what will be the square feet of half of the building?
2.42 square feet
We can just divide the given area by 2 as the building is square-shaped.
Dividing 4.84 by 2 = we get 2.42.
So half of the building measures 2.42 square feet.
Calculate √4.84 x 5.
11
The first step is to find the square root of 4.84 which is 2.2, the second step is to multiply 2.2 with 5.
So 2.2 x 5 = 11.
What will be the square root of (4 + 0.84)?
The square root is 2.2
To find the square root, we need to find the sum of (4 + 0.84). 4 + 0.84 = 4.84, and then √4.84 = 2.2.
Therefore, the square root of (4 + 0.84) is ±2.2.
Find the perimeter of the rectangle if its length ‘l’ is √4.84 units and the width ‘w’ is 3 units.
We find the perimeter of the rectangle as 10.4 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√4.84 + 3) = 2 × (2.2 + 3) = 2 × 5.2 = 10.4 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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