Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse operation is finding the square root. Square roots are used in various fields such as engineering, physics, and finance. Here, we will discuss the square root of 3.75.
The square root is the inverse operation of squaring a number. 3.75 is not a perfect square. The square root of 3.75 can be expressed in both radical and exponential forms. In radical form, it is expressed as √3.75, and in exponential form as (3.75)^(1/2). √3.75 ≈ 1.9365, which is an irrational number because it cannot be expressed as a fraction of two integers.
The prime factorization method is typically used for perfect square numbers. However, for non-perfect squares like 3.75, methods like long division and approximation are used. Let's explore these methods:
The long division method is ideal for non-perfect square numbers. Here's how to find the square root using this method:
Step 1: Begin by grouping the numbers from right to left. Since 3.75 is a decimal, consider it as 375 (shifting the decimal).
Step 2: Find a number whose square is less than or equal to 3. The number is 1, since 1^2 = 1. The quotient is 1, and the remainder is 2.
Step 3: Bring down 75 to make the new dividend 275. Double the current quotient (1), making the new divisor 2.
Step 4: Find n such that 2n × n ≤ 275. Consider n as 9. This gives 29 × 9 = 261.
Step 5: Subtract 261 from 275, giving a remainder of 14.
Step 6: Add decimal points and bring down two zeros, making the new dividend 1400.
Step 7: Find the new divisor by doubling the current quotient (19), making it 38. Find n such that 38n × n ≤ 1400. Take n as 3, giving 383 × 3 = 1149.
Step 8: Subtract 1149 from 1400, resulting in a remainder of 251.
Step 9: The current quotient is 1.93. Continue this process until you achieve the desired decimal precision.
The square root of 3.75 is approximately 1.936.
The approximation method provides an easy way to estimate square roots. Here’s how to find the square root of 3.75 using approximation:
Step 1: Identify the closest perfect squares around 3.75. The numbers are 1 (1^2) and 4 (2^2). Thus, √3.75 lies between 1 and 2.
Step 2: Use linear interpolation to approximate: (3.75 - 1) / (4 - 1) = 2.75 / 3 ≈ 0.9167
Step 3: Add this to the lower bound (1): 1 + 0.9167 = 1.9167
Thus, the square root of 3.75 is approximately 1.9167.
Students often make errors when calculating square roots, such as ignoring negative roots or misapplying methods. Let's explore common mistakes and how to avoid them.
Can you help Max find the area of a square box if its side length is given as √3.5?
The area of the square is approximately 12.25 square units.
The area of a square is given by side^2.
The side length is √3.5.
Area = side^2 = (√3.5)^2 = 3.5.
Therefore, the area of the square box is approximately 12.25 square units.
A square-shaped building measuring 3.75 square feet is built; if each of the sides is √3.75, what will be the square feet of half of the building?
Approximately 1.875 square feet
We divide the area by 2 since the building is square-shaped.
Dividing 3.75 by 2 gives approximately 1.875.
So, half of the building measures approximately 1.875 square feet.
Calculate √3.75 × 5.
Approximately 9.6825
First, find the square root of 3.75, which is approximately 1.9365.
Then multiply it by 5. 1.9365 × 5 ≈ 9.6825.
What will be the square root of (3.75 + 0.25)?
The square root is 2.
To find the square root, first calculate the sum of (3.75 + 0.25). 3.75 + 0.25 = 4, and √4 = 2.
Therefore, the square root of (3.75 + 0.25) is 2.
Find the perimeter of the rectangle if its length ‘l’ is √3.75 units and the width ‘w’ is 5 units.
The perimeter of the rectangle is approximately 13.873 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√3.75 + 5) ≈ 2 × (1.9365 + 5) ≈ 2 × 6.9365 ≈ 13.873 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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