Table Of Contents
Last updated on December 30th, 2024
Least Common Multiple (LCM) is the smallest positive integer that is divisible by both 36 and 45. By learning the following tricks, you can learn the LCM of 36 and 45 easily.
The LCM of 36 and 45 is 180. How did we get to this answer, though? That’s what we’re going to learn. We also see how we can find the LCM of 2 or more numbers in different ways.
We have already read about how you can approach finding the LCM of 2 or more numbers. Here is a list of those methods which make it easy to find the LCMs:
Method 1: Listing of Multiples
Method 2: Prime Factorization
Method 3: Division Method
Now let us delve further into these three methods and how it benefits us.
In this method, we will list all the multiples of 36 and 45. Then we will try to find a multiple that is present in both numbers.
For example,
Multiples of 36:
36, 72, 108, 144, 180, 216, 252, 288, 324, 360,…
Multiples of 45:
45, 90, 135, 180, 225, 270, 315, 360, 405, 450,…
The LCM of 36 and 45 is 180. 180 is the smallest number which can be divisible by both 36 and 45.
To find the LCM of 36 and 45 using the prime factorization method, we need to find out the prime factors of both the numbers. Then multiply the highest powers of the factors to get the LCM.
Prime Factors of 36 are: 22, 32
Prime Factors of 45 are: 32, 51
Multiply the highest power of both the factors: 22 × 32 × 51 = 2 × 2 × 3 × 3 × 5 = 180
Therefore, the LCM of 36 and 45 is 180.
To calculate the LCM using the division method. We will divide the given numbers with their prime numbers. The prime numbers should at least divide any one of the given numbers. Divide the numbers till the remainder becomes 1. By multiplying the prime factors, one can get LCM.
For finding the LCM of 36 and 45 we will use the following method.
By multiplying the prime divisors from the table, we will get the LCM of 36 and 45
2 × 2 × 3 × 3 × 5 = 180
The LCM of 36 and 45 is 180.
Find the missing number that would satisfy both conditions for the sequence of common multiples of 36 and 45 up to 540.Given sequence: 0, 180, 360, ?, 720.
A person buys 36 pencils and 45 pens. If they wish to distribute both items in equal groups without remainder, what is the maximum number of groups they can make?
If a=36 and b=45, prove that the relationship LCM(a, b)×GCF(a, b)=a×b holds true.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.