Last updated on May 26th, 2025
Roman numerals are the way of expressing numbers using symbols. I, V, X, L, C, D, and M are the symbols we use. Roman Numerals are used in royal titles, book names, sequences, and so on. Here we will be discussing Roman Numerals, rules, and examples.
The royal titles, such as Henry I, Henry II, and so on. Have you noticed the names and wondered what these symbols (I and II) represented?
Those are the Roman Numerals. Earlier, people used to count using fingers, sticks, bones, etc. When life became complex, a standard form was required to count. Ancient Romans used the Roman Numeral system to count. I (1), V (5), X (10), L (50), C (100), D (500), and M (1000) are the symbols we use to count.
In Roman Numerals, we use DCCXI to represent 711, here D is 500, CC is 200, and XI is 11.
Let’s learn more about Roman numerals and how we write them.
There are certain basic rules to write a number in Roman Numerals. In this section, let’s discuss some basic rules that need to be remembered when writing a number in Roman numerals.
The addition method is used when the smaller number is placed after the larger number, then it is the addition method. For example, DCCXI → D + CC + X + I → 500 + 200 + 10 + 1 = 711.
To write a large number, there are certain Roman Numerals that can be repeated up to three times. For example, CCC → 300.
If a small number is followed by a large number in Roman Numerals, we subtract the smaller number from the large number, it is a subtraction method. For example, IX → X - I → 10 - 1 = 9.
The symbols cannot be repeated more than three times, and some symbols like V, L, and D cannot be repeated. For example, we won't write VV for 10; instead, we use X, and 8 we write as VIII, not IIIIIIII.
Let’s now learn how to write 711 in Roman Numerals. Follow these methods to write the number in Roman Numerals.
In the expansion method, based on the place value, the number is broken down. In this section, we will learn how to write 711 in Roman numerals using the expansion method.
To write 711 in Roman Numerals, follow the steps:
Step 1: The number is broken based on the place value, such as ones, tens, hundreds, etc.
For 711, we write it as 500 + 200 + 10 + 1.
Step 2: Converting the number into Roman Numerals:
500 in Roman Numerals — D
200 in Roman Numerals — CC
10 in Roman Numerals — X
1 in Roman Numerals — I
Step 3: Combining them Roman Numerals together.
Therefore, 711 in Roman Numerals is D (500) + CC (200) + X (10) + I (1) = DCCXI.
When writing a large number into Roman Numerals, we group the number.
To write 711 in Roman Numerals, we group 711 as 500 + 200 + 10 + 1.
500 in Roman Numerals — D
200 in Roman Numerals — CC
10 in Roman Numerals — X
1 in Roman Numerals — I
So, 711 is written as DCCXI in Roman Numerals.
Students make mistakes when writing a number in Roman Numerals. To master Roman Numerals, we can learn a few common mistakes and the ways to avoid them.
A historian discovers a document indicating that an ancient civilization constructed DCCXI aqueducts over LXI years. Determine the average number of aqueducts built per year.
The average number of aqueducts built per year is XI.
To find the average, divide the total number of aqueducts by the total number of years.
DCCXI = 711
LXI = 61
Therefore, DCCXI / LXI = 711 / 61 = 11.
11 in Roman numerals is XI.
An archaeologist finds a record stating that an ancient city had a population of DCCXI people, and over the years, the population increased by CCXL. What is the new population in Roman numerals?
The new population is CMLI.
To find the new population, add the increase to the original population.
DCCXI = 711
CCXL = 240
711 + 240 = 951
951 in Roman numerals is CMLI
A scribe records that a shipment of DCCXI barrels of olive oil was divided evenly among LXXI merchants. How many barrels did each merchant receive?
Each merchant received X barrels.
To find the number of barrels per merchant, divide the total number of barrels by the number of merchants.
DCCXI = 711
LXXI = 71
711 / 71 = 10
10 in Roman numerals is X.
A historian finds a table showing that an ancient festival lasted for DCCXI hours over the course of several days. If each day had XI hours of festivities, how many days did the festival last?
The festival lasted for LXV days.
To find the number of days, divide the total hours by the hours per day.
DCCXI = 711
XI = 11
711 / 11 = 65
65 in Roman numerals is LXV.
Calculate the difference between DCCXI and CDLXI in Roman numerals.
The diThe difference is CCXLX.
Subtract the smaller number from the larger number.
DCCXI = 711
CDLXI = 461
711 - 461 = 250
250 in Roman numerals is CCL.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.