Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the fields of mathematics, engineering, and science. Here, we will discuss the square root of 3.25.
The square root is the inverse of the square of a number. 3.25 is not a perfect square. The square root of 3.25 is expressed in both radical and exponential form. In the radical form, it is expressed as √3.25, whereas (3.25)^(1/2) in the exponential form. √3.25 ≈ 1.80278, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is more suitable for perfect square numbers. However, for non-perfect square numbers like 3.25, the long-division method and approximation method are used. Let us now learn the following methods:
The long division method is particularly effective for non-perfect square numbers. In this method, we focus on finding the square root through a series of steps.
Step 1: To begin, set the number 3.25 in decimal form and consider it as 325.
Step 2: Pair the digits starting from the decimal point. In this case, we have 3.25, so the pair is 32 and 5.
Step 3: Find a number whose square is less than or equal to 3. The number is 1 because 1 × 1 ≤ 3.
Step 4: Subtract 1² from 3 to get the remainder 2, and bring down 2 to make it 22.
Step 5: Double the divisor (1) to get 2 and find a digit to append to 2 to make it less than or equal to 225. That digit is 8 because 28 × 8 = 224.
Step 6: Subtract 224 from 225 to get the remainder 1. Bring down 00 to make it 100.
Step 7: Double the divisor 18 to get 36 and determine a digit to append to 36 to make it less than or equal to 100. That digit is 2 because 362 × 2 = 724.
Step 8: Continue this process until the desired precision is achieved.
The result is approximately 1.80278.
The approximation method is another approach for finding square roots. It involves estimating the value based on nearby perfect squares.
Step 1: Identify the nearest perfect squares surrounding 3.25. The closest perfect squares are 1 (1²) and 4 (2²), so √3.25 is between 1 and 2.
Step 2: Use interpolation to approximate the value. Given that 3.25 is closer to 4 than to 1, we can estimate the square root is closer to 2.
Step 3: Using the formula (Given number - smaller perfect square) / (Larger perfect square - smaller perfect square), we get: (3.25 - 1) / (4 - 1) = 2.25 / 3 ≈ 0.75
Step 4: Adding this to the lower boundary value gives us 1 + 0.75 = 1.75.
Adjusting through trial and error, we find that √3.25 ≈ 1.80278.
When calculating the square root, students might make errors such as omitting the negative square root or misplacing the decimal point. Let's explore some common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √3.25?
The area of the square is approximately 10.5601 square units.
The area of the square = side².
The side length is given as √3.25 ≈ 1.80278.
Area = (√3.25)² = 1.80278 × 1.80278 ≈ 3.25.
Therefore, the area of the square box is approximately 3.25 square units.
A square-shaped garden measuring 3.25 square meters is built; if each of the sides is √3.25, what will be the square meters of half of the garden?
1.625 square meters
We can divide the given area by 2 since the garden is square-shaped.
Dividing 3.25 by 2, we get 1.625.
So, half of the garden measures 1.625 square meters.
Calculate √3.25 × 5.
Approximately 9.0139
First, find the square root of 3.25, which is approximately 1.80278.
Then, multiply 1.80278 by 5.
So 1.80278 × 5 ≈ 9.0139.
What will be the square root of (2 + 1.25)?
The square root is approximately 1.80278.
To find the square root, we compute the sum of (2 + 1.25), which totals 3.25. √3.25 ≈ 1.80278.
Therefore, the square root of (2 + 1.25) is approximately 1.80278.
Find the perimeter of the rectangle if its length ‘l’ is √3.25 units and the width ‘w’ is 5 units.
The perimeter of the rectangle is approximately 13.6056 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√3.25 + 5) ≈ 2 × (1.80278 + 5) ≈ 2 × 6.80278 ≈ 13.6056 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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