Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse of the square is a square root. The square root is used in fields like vehicle design, finance, etc. Here, we will discuss the square root of 6.4.
The square root is the inverse of the square of a number. 6.4 is not a perfect square. The square root of 6.4 is expressed in both radical and exponential form. In the radical form, it is expressed as √6.4, whereas (6.4)^(1/2) in the exponential form. √6.4 ≈ 2.52982, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, for non-perfect square numbers, methods like the long division method and approximation method are used. Let us learn about the following methods:
The long division method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us learn how to find the square root using the long division method, step by step.
Step 1: To begin, we need to group the numbers from right to left. For 6.4, treat it as 64 by considering two decimal places.
Step 2: Find n whose square is less than or equal to 6. We can say n = 2 because 2² = 4, which is less than 6. The quotient is 2, and after subtracting, the remainder is 2.
Step 3: Bring down 40 (from 4.0). Add the old divisor with the same number: 2 + 2 = 4, which will be our new divisor.
Step 4: Find n such that 4n × n ≤ 240. Let n = 5, then 45 × 5 = 225.
Step 5: Subtract 225 from 240, and the remainder is 15.
Step 6: Since the remainder is less than the divisor, add a decimal point and two zeroes to the remainder to make it 1500.
Step 7: Find the new divisor that is 49 because 495 × 5 = 2475.
Step 8: Subtract 2475 from 1500 to get a new remainder. Continue this process until you reach the desired accuracy.
So the square root of √6.4 ≈ 2.53.
The approximation method is an easy method for finding the square roots of non-perfect squares. Here’s how to find the square root of 6.4 using approximation.
Step 1: Identify the closest perfect squares around 6.4.
The smallest perfect square below 6.4 is 4, and the largest perfect square above 6.4 is 9. √6.4 falls between 2 and 3.
Step 2: Apply the formula: (Given number - smallest perfect square) / (Greater perfect square - smallest perfect square). For 6.4, (6.4 - 4) / (9 - 4) = 0.48.
Add this decimal to the smaller perfect square root: 2 + 0.53 = 2.53.
Therefore, the square root of 6.4 is approximately 2.53.
Students often make mistakes while finding square roots, such as forgetting about the negative square root or skipping methods like long division. Let's review some common errors in detail.
Can you help Max find the area of a square box if its side length is given as √6.4?
The area of the square is approximately 16.04 square units.
The area of the square = side².
The side length is given as √6.4.
Area of the square = (√6.4)² ≈ 2.53 × 2.53 ≈ 16.04.
Therefore, the area of the square box is approximately 16.04 square units.
A square-shaped building measuring 6.4 square feet is built; if each of the sides is √6.4, what will be the square feet of half of the building?
3.2 square feet
Since the building is square-shaped, dividing the given area by 2 gives the area of half of the building.
Dividing 6.4 by 2 = 3.2.
So half of the building measures 3.2 square feet.
Calculate √6.4 × 5.
Approximately 12.65
First, find the square root of 6.4, which is approximately 2.53.
Then multiply 2.53 by 5.
So, 2.53 × 5 ≈ 12.65.
What will be the square root of (4 + 2.4)?
The square root is approximately 2.83.
To find the square root, first find the sum of (4 + 2.4). 4 + 2.4 = 6.4, and then √6.4 ≈ 2.53.
Therefore, the square root of (4 + 2.4) is approximately ±2.53.
Find the perimeter of the rectangle if its length ‘l’ is √6.4 units and the width ‘w’ is 3.8 units.
The perimeter of the rectangle is approximately 12.66 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√6.4 + 3.8) = 2 × (2.53 + 3.8) ≈ 2 × 6.33 ≈ 12.66 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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