Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse of the square is a square root. The square root is used in various fields such as vehicle design and finance. Here, we will discuss the square root of 4.8.
The square root is the inverse of squaring a number. Since 4.8 is not a perfect square, its square root is expressed in both radical and exponential form. In radical form, it is expressed as √4.8, whereas in exponential form it is (4.8)^(1/2). √4.8 ≈ 2.19089, which is an irrational number because it cannot be expressed as a simple fraction.
For non-perfect square numbers, methods like the long division method and approximation method are used since the prime factorization method is not applicable. Let us now learn these methods:
The long division method is useful for finding square roots of non-perfect square numbers. Here is how to find the square root of 4.8 using this method, step by step:
Step 1: First, we need to group the numbers from right to left. Since 4.8 is a single-digit decimal, we consider 4.8 as 48 with a decimal point later.
Step 2: Find a number (n) whose square is less than or equal to 4. We choose n as 2 because 2^2 = 4.
Step 3: Subtract 4 from 4, resulting in 0. Bring down 80, making the new dividend 80.
Step 4: Double the current quotient (2) to get 4, which will be the start of the new divisor.
Step 5: Find a digit (x) such that 4x * x is less than or equal to 80. Choose x as 2, because 42 * 2 = 84 is too large.
Step 6: Use 41 * 1 = 41. Subtract 41 from 80, resulting in 39.
Step 7: Since 39 is smaller than 41, we add a decimal point and bring down two zeroes, making the new dividend 3900.
Step 8: Double the current quotient (21) to get 42, which will be the first part of the new divisor.
Step 9: Find a digit (y) such that 42y * y is less than or equal to 3900. Choose y as 9, because 429 * 9 = 3861 is less than 3900.
Step 10: Subtract 3861 from 3900, resulting in 39. The quotient is 2.19.
The approximate value of √4.8 is 2.19.
The approximation method is a simpler way to find square roots. Here is how to find the square root of 4.8 using this method:
Step 1: Identify the closest perfect squares to 4.8.
The closest perfect squares are 4 (2^2) and 9 (3^2). Thus, √4.8 is between 2 and 3.
Step 2: Use linear interpolation to estimate the square root: (4.8 - 4) / (9 - 4) = 0.8 / 5 = 0.16 Add this to the lower bound: 2 + 0.16 = 2.16
Therefore, √4.8 is approximately 2.16.
Students often make errors when finding square roots, such as forgetting about the negative square root, or misapplying methods. Here are some common mistakes to watch out for:
Can you help Max find the area of a square box if its side length is given as √4.8?
The area of the square is approximately 4.8 square units.
The area of the square = side^2.
The side length is given as √4.8.
Area of the square = (√4.8)^2 = 4.8.
Therefore, the area of the square box is approximately 4.8 square units.
A square-shaped garden measures 4.8 square meters; if each side is √4.8 meters, what is the area of half the garden?
2.4 square meters
To find half the area of the garden, divide the total area by 2.
Dividing 4.8 by 2 gives 2.4.
Thus, half of the garden measures 2.4 square meters.
Calculate √4.8 × 5.
Approximately 10.95
First, find the square root of 4.8, which is approximately 2.19.
Then, multiply 2.19 by 5.
So, 2.19 × 5 ≈ 10.95.
What will be the square root of (4 + 0.8)?
The square root is approximately 2.19.
To find the square root, first find the sum of (4 + 0.8), which is 4.8.
Then find √4.8, which is approximately 2.19.
Find the perimeter of a rectangle if its length 'l' is √4.8 units and the width 'w' is 4 units.
The perimeter of the rectangle is approximately 12.38 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√4.8 + 4) ≈ 2 × (2.19 + 4) = 2 × 6.19 ≈ 12.38 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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