Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in fields like vehicle design, finance, etc. Here, we will discuss the square root of 0.8.
The square root is the inverse of the square of the number. 0.8 is not a perfect square. The square root of 0.8 is expressed in both radical and exponential form. In the radical form, it is expressed as √0.8, whereas (0.8)^(1/2) in the exponential form. √0.8 ≈ 0.89443, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where long-division and approximation methods are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. For 0.8, we can express it as a fraction (8/10) or (4/5). Since 0.8 is not a perfect square, the prime factorization approach is not straightforward for decimal or fraction values without converting to a base that can be factored easily.
Hence, the prime factorization method is not typically used for decimals like 0.8.
The long division method is particularly useful for non-perfect square numbers. Here's how to find the square root using the long division method, step by step:
Step 1: Begin by considering 0.8 as 80/100 or 0.80 for ease of calculation.
Step 2: Start with the closest perfect square less than 80, which is 64 (√64=8).
Step 3: Use the long division method to find √0.80, bringing down pairs of zeros as needed to find more decimal places.
Step 4: Continue the division process until you reach the desired precision.
Step 5: The result will be √0.8 ≈ 0.89443.
The approximation method is another method for finding square roots, useful for gaining a quick estimate. Here's how to find the square root of 0.8 using approximation:
Step 1: Identify perfect squares around 0.8. The closest perfect squares are 0.64 (0.8²) and 1 (1²), which are near 0.8.
Step 2: Recognize that √0.64 = 0.8 and √1 = 1, so √0.8 falls between 0.8 and 1.
Step 3: Use an average method or linear interpolation to find a closer approximation if necessary.
Step 4: The approximated value is √0.8 ≈ 0.89443.
Students often make mistakes while finding square roots, such as overlooking the negative square root or misapplying methods. Let's examine a few common errors in detail.
Can you help Max find the area of a square box if its side length is given as √0.8?
The area of the square is approximately 0.8 square units.
The area of a square = side².
The side length is given as √0.8.
Area of the square = (√0.8)² = 0.8.
Therefore, the area of the square box is approximately 0.8 square units.
A square-shaped garden measuring 0.8 square meters is built; if each of the sides is √0.8, what will be the square meters of half of the garden?
0.4 square meters
Divide the given area by 2 as the garden is square-shaped.
Dividing 0.8 by 2, we get 0.4. So, half of the garden measures 0.4 square meters.
Calculate √0.8 × 5.
Approximately 4.47215
The first step is to find the square root of 0.8, which is approximately 0.89443.
The second step is to multiply 0.89443 by 5. So, 0.89443 × 5 ≈ 4.47215.
What will be the square root of (0.6 + 0.2)?
The square root is approximately 0.89443.
To find the square root, first find the sum of (0.6 + 0.2). 0.6 + 0.2 = 0.8, and then √0.8 ≈ 0.89443.
Therefore, the square root of (0.6 + 0.2) is approximately ±0.89443.
Find the perimeter of a rectangle if its length ‘l’ is √0.8 units and the width ‘w’ is 0.5 units.
The perimeter of the rectangle is approximately 2.78886 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√0.8 + 0.5) = 2 × (0.89443 + 0.5) = 2 × 1.39443 ≈ 2.78886 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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