Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 7.6.
The square root is the inverse of the square of the number. 7.6 is not a perfect square. The square root of 7.6 is expressed in both radical and exponential form. In the radical form, it is expressed as √7.6, whereas (7.6)^(1/2) in the exponential form. √7.6 ≈ 2.75681, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, for non-perfect square numbers, methods such as the long-division method and approximation method are used. Let us now learn the following methods:
The long division method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin with, treat the number as 7.60, and group the numbers from right to left.
Step 2: Find a number whose square is less than or equal to 7. Here, 2 satisfies this condition because 2 × 2 = 4.
Step 3: Subtract 4 from 7, giving a remainder of 3. Bring down 60 to make it 360.
Step 4: Double the quotient obtained (2) to form part of the new divisor, making it 4_.
Step 5: Find a digit to fill in the blank that, when multiplied by the new divisor, does not exceed 360. Here, 7 works since 47 × 7 = 329.
Step 6: Subtract 329 from 360, giving a remainder of 31.
Step 7: Since we are not done, add a decimal point and bring down two zeros, making it 3100.
Step 8: Continue this process to refine the answer to two decimal places. The quotient will approximate to 2.75.
The approximation method is another technique for finding square roots. This is an easy method to find the square root of a given number. Let us learn how to find the square root of 7.6 using the approximation method.
Step 1: Identify the closest perfect squares around 7.6.
The closest perfect square less than 7.6 is 4, and the closest perfect square greater than 7.6 is 9. √7.6 falls between 2 and 3.
Step 2: Use interpolation: (Given number - smaller perfect square) / (greater perfect square - smaller perfect square) = (7.6 - 4) / (9 - 4) = 0.72
Step 3: Add this result to the smaller perfect square's root: 2 + 0.72 = 2.72
Thus, the approximate square root of 7.6 is about 2.72.
Students often make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Here are a few common mistakes students may make.
Can you help Max find the area of a square if its side length is given as √7.6?
The area of the square is 7.6 square units.
The area of a square = side².
The side length is given as √7.6.
Area of the square = side² = √7.6 × √7.6 = 7.6.
Therefore, the area is 7.6 square units.
A square-shaped park measures 7.6 square meters in area. If each side is √7.6, what will be the area of half of the park?
3.8 square meters
To find half the area of the park, divide the total area by 2. 7.6 / 2 = 3.8.
Thus, half the park measures 3.8 square meters.
Calculate √7.6 × 3.
8.27043
First, find the square root of 7.6, which is approximately 2.75681.
Then multiply 2.75681 by 3. 2.75681 × 3 ≈ 8.27043.
What will be the square root of (3.6 + 4)?
The square root is 2.8.
To find the square root, first find the sum of (3.6 + 4). 3.6 + 4 = 7.6. √7.6 ≈ 2.8.
Therefore, the square root of (3.6 + 4) is ±2.8.
Find the perimeter of a rectangle if its length 'l' is √7.6 units and the width 'w' is 5 units.
The perimeter of the rectangle is approximately 15.51 units.
Perimeter of a rectangle = 2 × (length + width).
Perimeter = 2 × (√7.6 + 5) ≈ 2 × (2.75681 + 5) ≈ 15.51 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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