Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 3.5
The square root is the inverse of the square of the number. 3.5 is not a perfect square. The square root of 3.5 is expressed in both radical and exponential form. In the radical form, it is expressed as √3.5, whereas (3.5)^(1/2) is in the exponential form. √3.5 ≈ 1.8708, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where long-division and approximation methods are used. Let us now learn the following methods:
The long division method is particularly used for non-perfect square numbers. Let us now learn how to find the square root using the long division method, step by step:
Step 1: Start by placing 3.5 under the long division symbol, treating it as 35 to avoid dealing with a decimal initially, then consider it as 3500.
Step 2: Find the largest number whose square is less than or equal to 35. Here, it is 5 because 5 × 5 = 25, which is less than 35.
Step 3: Subtract 25 from 35 to get 10 and bring down the next two zeros, making it 1000.
Step 4: Double the quotient (5) to get 10 as the new divisor.
Step 5: Find a number (n) such that 10n × n ≤ 1000. Here, n = 9 works because 109 × 9 = 981.
Step 6: Subtract 981 from 1000 to get 19 and bring down the next two zeros, making it 1900.
Step 7: Continue this process to get decimal places as needed.
The next steps will eventually give a quotient of about 1.8708.
Approximation is another method for finding the square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 3.5 using the approximation method.
Step 1: Find the closest perfect squares around 3.5. The closest perfect squares are 1 (1^2) and 4 (2^2). Thus, √3.5 falls between 1 and 2.
Step 2: Use linear interpolation to approximate the decimal. The formula is: (Given number - smaller perfect square) / (larger perfect square - smaller perfect square). For √3.5: (3.5 - 1) / (4 - 1) = 2.5/3 ≈ 0.8333.
Step 3: Add this decimal to the smaller square root: 1 + 0.8333 = 1.8333, but refine it further through more precise interpolation to get approximately 1.8708.
Students make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Let us look at a few common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √3.5?
The area of the square is approximately 3.5 square units.
The area of the square = side^2.
The side length is given as √3.5.
Area of the square = side^2 = √3.5 × √3.5 = 3.5.
Therefore, the area of the square box is approximately 3.5 square units.
A square-shaped building measuring 3.5 square meters is built; if each of the sides is √3.5, what will be the square meters of half of the building?
1.75 square meters
We can divide the given area by 2 as the building is square-shaped.
Dividing 3.5 by 2 = we get 1.75.
So half of the building measures 1.75 square meters.
Calculate √3.5 × 5.
Approximately 9.354.
The first step is to find the square root of 3.5, which is approximately 1.8708.
Then multiply 1.8708 with 5.
So 1.8708 × 5 ≈ 9.354.
What will be the square root of (3 + 0.5)?
The square root is approximately 1.8708.
To find the square root, calculate the sum of (3 + 0.5) 3 + 0.5 = 3.5, and then √3.5 ≈ 1.8708.
Therefore, the square root of (3 + 0.5) is approximately ±1.8708.
Find the perimeter of the rectangle if its length ‘l’ is √3.5 units and the width ‘w’ is 3 units.
We find the perimeter of the rectangle as approximately 9.7416 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√3.5 + 3) ≈ 2 × (1.8708 + 3) ≈ 2 × 4.8708 ≈ 9.7416 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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