Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse of squaring a number is finding its square root. The square root is used in fields like vehicle design, finance, etc. Here, we will discuss the square root of 1.1.
The square root is the inverse of squaring a number. 1.1 is not a perfect square. The square root of 1.1 is expressed in both radical and exponential form. In the radical form, it is expressed as √1.1, whereas (1.1)^(1/2) in the exponential form. √1.1 ≈ 1.0488, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, for non-perfect square numbers like 1.1, methods such as the long division method and approximation method are used. Let us learn the following methods:
The long division method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step.
Step 1: Group the numbers from right to left. For 1.1, consider it as 11 (ignoring the decimal for initial steps).
Step 2: Find n whose square is less than or equal to 1. We can say n is '1' because 1 × 1 ≤ 1. Now the quotient is 1, and after subtracting 1 - 1, the remainder is 0.
Step 3: Bring down the next digit, which is 1, to make the new dividend 10.
Step 4: The new divisor is twice the quotient from step 2, which is 2.
Step 5: Determine n such that 2n × n ≤ 10. n is 4, as 2 × 4 × 4 = 8.
Step 6: Subtract 8 from 10 to get a remainder of 2.
Step 7: Add a decimal point to the quotient and bring down a pair of zeroes to make the new dividend 200.
Step 8: The new divisor is 28 (from 24 + 4).
Step 9: Determine n such that 28n × n ≤ 200. n is 7, as 28 × 7 = 196.
Step 10: Subtract 196 from 200 to get a remainder of 4.
Step 11: Continue this process to obtain more decimal places if necessary.
So the square root of √1.1 ≈ 1.0488.
The approximation method is another method for finding square roots; it is an easy method to estimate the square root of a given number. Let us learn how to find the square root of 1.1 using the approximation method.
Step 1: Identify two perfect squares between which 1.1 falls. The closest perfect squares are 1 (1^2) and 1.21 (1.1^2).
Step 2: Use the formula: (Given number - smaller perfect square) / (larger perfect square - smaller perfect square). Using the formula: (1.1 - 1) / (1.21 - 1) ≈ 0.476.
Step 3: The approximate square root is 1 + 0.0488 = 1.0488. So the square root of 1.1 is approximately 1.0488.
Students often make mistakes while finding the square root, such as forgetting about the negative square root. Skipping steps in methods like long division can also lead to errors. Let us examine a few common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √1.1?
The area of the square is approximately 1.1 square units.
The area of the square = side².
The side length is given as √1.1.
Area of the square = (√1.1)² = 1.1.
Therefore, the area of the square box is approximately 1.1 square units.
A rectangle has an area of 1.1 square meters. If one side is √1.1, what is the length of the other side?
The other side is approximately 1 meter.
We can find the length of the other side by dividing the area by one side:
Area / side = 1.1 / √1.1 ≈ 1 meter.
Calculate √1.1 × 5.
5.244
The first step is to find the square root of 1.1, which is approximately 1.0488.
Multiply 1.0488 by 5. 1.0488 × 5 ≈ 5.244.
What will be the square root of (1 + 0.1)?
The square root is approximately 1.0488.
To find the square root, compute the sum (1 + 0.1) = 1.1, and then find the square root of 1.1, which is approximately 1.0488.
Find the perimeter of a rectangle if its length ‘l’ is √1.1 units and the width ‘w’ is 1 unit.
The perimeter of the rectangle is approximately 4.0976 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√1.1 + 1) = 2 × (1.0488 + 1) = 2 × 2.0488 = 4.0976 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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